Approximate size of the nucleus of Nickel(mass=64,at. no.=28) is:
a)3fm b)4fm
c)5fm d)2fm..
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Answered by
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Nuclear size is given by the expression:
r = R0A1/3
where r is the radius of the nucleus
R0 is a constant whose value is equal to 1.25 fm (fm is fermi units)
A is atomic mass of element
Thus for 64Ni, we have
r = 1.25 ×(64)1/3
r = 1.25 ×4
r = 5 fm
Thus nuclear size of Ni is 5 fm.
r = R0A1/3
where r is the radius of the nucleus
R0 is a constant whose value is equal to 1.25 fm (fm is fermi units)
A is atomic mass of element
Thus for 64Ni, we have
r = 1.25 ×(64)1/3
r = 1.25 ×4
r = 5 fm
Thus nuclear size of Ni is 5 fm.
munmisnigdha:
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