approximate value of1/cube root of 8.08
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Fx= 1/ qube root of x
So F' x = -1/3× x^ -4/3
Now use
f( x+ h) = h f'( x ) + f( x)
here h= 0.08
f( x) = 1/2
So f( x+ h) = 1.9983
So qube root of its will be 1.9983
So F' x = -1/3× x^ -4/3
Now use
f( x+ h) = h f'( x ) + f( x)
here h= 0.08
f( x) = 1/2
So f( x+ h) = 1.9983
So qube root of its will be 1.9983
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can u keep some what clearly
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