Approximately how many amperes of current flow in a circuit with 40v source and 6.8k of resistance
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I = V/R = 40/6.8 = 5.9 approximately.
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Answer:
Given that,
- V = 40v,
- R = 6.8Kohm,
- I = V/R.
I = 40/6.8*(10^-3).
I = 5.882mA.
That is right answer.!!
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