Physics, asked by Ashishmishra6263, 1 year ago

Approximately how many amperes of current flow in a circuit with 40v source and 6.8k of resistance

Answers

Answered by NarwalVarsha
0
I = V/R = 40/6.8 = 5.9 approximately.
Answered by Sadhiti
7

Answer:

Given that,

  • V = 40v,
  • R = 6.8Kohm,
  • I = V/R.

I = 40/6.8*(10^-3).

\longmapsto I = 5.882mA.

That is right answer.!!

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