Approximately how many milliamperes of current fow through a circuit with a 40 v source and 6.8k ohm of resistance
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let the current =IA
potential different V =40v
resistance R=6.8k ohm =6.8x1000=6800ohm
using ohm's law, V=IR
or, I=V/R
I=40/6800
I=5.88 x 10^-3 ampere
I=5.88 x 10^-6 mA [1mA =10^-3 ampere ]
potential different V =40v
resistance R=6.8k ohm =6.8x1000=6800ohm
using ohm's law, V=IR
or, I=V/R
I=40/6800
I=5.88 x 10^-3 ampere
I=5.88 x 10^-6 mA [1mA =10^-3 ampere ]
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