Question

approximately the length of the wire of specific resistance 50 × 10-⁸Ω is needed to make resistance of 4Ω​

Answer 1

Answer:

$resistence = p(rho)l \div a$

$l = ra \div p$

4.2×π(0.4/2*10^-3) ^2

______________

4.8*10^-8

$= 1.1m$

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