Question

Approximately what is the length of the rope for the kite sale in order to pull the ship at an angle of 45° and b at a vertical height of 150 as shown in the diagram opposite

Answer 1

Answer:

212m is the answer of this question

Answer 2

Given:

angle=45°

vertical height= 150m

To find:

Length of the rope

Solution:

Let the length of the rope be $x$.

Now, the rope forms the hypotenuse and the vertical height forms the perpendicular.

So we can write,

$sin 45$°$=\frac{length of rope}{vertical distance}$

⇒$\frac{1}{\sqrt{2} }=\frac{150}{x}$

⇒$x=150$×$\sqrt{2}$

⇒$x=212.13$

Hence, the length of the rope is 212.13m.