Question

Approximately what mass of CuSO4 • 5H2O (250 g mol-1) is required to prepare 250 mL of 0.10 M copper(II) sulfate solution?

Answer 1

Explanation:

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Answer 2

Required mass of CuSO₄.5H₂O to prepare 250 ml of 0.10 M is 6.25 g.

Step by step explanation:

• The formula to find molarity is;

        M = $\frac{W* 1000 }{M.M* V(ml)}$

M is Molarity

W is mass of Solute

M.M is the molar mass of solute

V is the volume of solution in ml

• Given data;

we have the M = 0.10M, M.M of CuSO₄.5H₂O= 250 g $mol^{-1}$ , V = 250 ml

• Calculation of required mass of CuSO₄.5H₂O;

by rearranging the formula, we get

W = $\frac{M*M.M* V(ml)}{1000}$  and by putting all given data we get our answer and the required mass of CuSO₄.5H₂O is 6.25 g .