Question

APQ is a triangle in which AP = AQ. If the bisectors of P and Q meet AQ

and AP in D and E respectively, D and E are midpoint of AQ and AP. Prove that

PD = QE.
pls help​

Answer 1

Step-by-step explanation:

In △APB and △AQB

AP=AQ (Given)

BP=BQ (Given)

AB=AB (Common Side)

∴△APB≅△AQB(S.S.S. congruency)

⇒∠PAB=∠QAB(C.P.C.T.C.)

⇒∠PBA=∠QBA(C.P.C.T.C.)

HOPE IT HELPS

Thus, AB is bisector of ∠PAQ and ∠PBQ