Aqua solution of dibasic acid gram molecular weight is 118 containing 35.4 grams of acid per litre of solution has density 1.0 077 gram per ml find molarity and molality
Answers
Explanation:
Given conditions ⇒
Mass of the acid in its aqueous solution = 35.4 g.
Molar mass of the succinic Acid = 118 g/mole.
Volume of the solution = 1 liter. = 1000 cm³.
Now, Let us First expressed the concentration of solution in Molarity.
∵ Molarity = No. of moles of the solute (or Acid)/Volume of the Solution in liter.
No. of moles of the solute or acid = Mass/Molar Mass
= 35.4/118
= 0.3
∴ Molarity of the solution = 0.3/1
= 0.3 M.
Hence, the Molarity of the solution is 0.3.
Now, We can also Express the concentration of the solution in terms of Molality.
Given ⇒
Density of the solution = 1.0077 g/cm³.
∵ Density = Mass/Volume
∴ Mass = Density × Volume
∴ Mass = 1.0077 × 1000
∴ Mass of the solution = 1007.7 grams.
We know, Mass of the Solution = Mass of the Solute (or Acid) + Mass of the Solvent (or Water)
∴ Mass of the Solvent (or Water) = Mass of the Solution - Mass of the Acid.
= 1007.7 - 35.4
= 972.3 g
= 0.9723 kg.
∵ Molality = No. of moles of the Solute (or Acids)/Mass of the solvent in kg.
= 0.3/0.9723
= 0.308 m.
Hence, the Molality of the solution is 0.308 m.
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