aquatic equation of one root is 2 + root 5 by 2 then find the quadratic equation
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2
Answer:
Answer:
The required quadratic equation is x^2-4x-1=0x
2
−4x−1=0
Step-by-step explanation:
Given : One root of quadratic equation is 2+\sqrt{5}2+
5
To find : The quadratic equation
Solution :
we know, if 2+\sqrt{5}2+
5
is one of the root of quadratic equation then,
x=2+\sqrt{5}x=2+
5
x-2=\sqrt{5}x−2=
5
Squaring both side,
(x-2)^2=(\sqrt{5})^2(x−2)
2
=(
5
)
2
x^2+4-4x=5x
2
+4−4x=5
x^2+4-4x-5=0x
2
+4−4x−5=0
x^2-4x-1=0x
2
−4x−1=0
Therefore, The required quadratic equation is x^2-4x-1=0x
2
−4x−1=0 .
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