Question

Aqueous NaOH solution is labelled as 10./. by weight mole fraction of the solute in it is

Answer 1

Given:

Percentage of solute (NaOH) = 10%

To find:

Mole fraction of solute

Formula to be used:

Mole fraction = $\frac{Number of moles of solute}{Total moles of solution}$

Calculation:

Solute + Solvent = Solution

10% of NaOH (Solute) = 100g of NaOH in 1 liter.

As 10% is NaOH, 90% is composed of water.

90% Water (Solvent) = 900g in 1 liter.

With the molar mass and calculated mass, number of moles in solvent and solute is calculated as shown below:

No of moles of NaOH (Solute)  = $\frac{100}{40} = 2.5$

No. of moles of $H_2O$ (Solvent) = $\frac{900}{18}= 50$

∴ Total number of moles present in solution

= No. of moles of solute + No. of moles of solvent

= 2.5 + 50

= 52.50 moles

Mole fraction of the NaOH is the given solution = $\frac{No. of moles of solute}{Total no. of moles in solution} = \frac{2.5}{52.5} = 0.476 moles$

Conclusion:

The mole fraction of solute is calculated as 0.476 moles.

Learn more about mole fraction

Mole fraction of solute in aqueous solution of 30% urea (by mass) is​

https://brainly.in/question/10578811

The mole fraction of c2h5oh in 5 molal aqueous ethyl alcohol solution is

https://brainly.in/question/3590943