aqueous sodium hydroxide solution is labelled as 10% by weight mole fraction of solute in it
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10%NaOh means 10g of NaOh is present in 90 g of solvent so moles of NaOH
10÷39.9= 0.250
moles of H2O = 90÷18.01=1.054
mole fraction =0.250÷(0.250+1.054)=0.1917M
10÷39.9= 0.250
moles of H2O = 90÷18.01=1.054
mole fraction =0.250÷(0.250+1.054)=0.1917M
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