Question

AR=3cm BR=7cm PQ=8cm find the distance of PQ from O​

Answer 1

Answer:

AB bisects chord PQ at point C.

Therefore,

PR=QR=8cm

RB=4cm

Let, radius OA=OB=r

OB=OR+RB

=>r=OR+4

=>OR=r−4 (i)

Now,

OP

2

=OR

2

+PR

2

=>r

2

=(r−4)

2

+8

2

(using (i)

=>r

2

=r

2

−8r+16+64

=>8r=80

=>r=10cm

The radius of the circle is 10cm