Question

Ar agarwal subtract(2a-3b+4c)from the sum of (a+3b-4c),(4a-b+9c)and (-2b+3c-a)

Answer 1

[(a+3b-4c)+(4a-b+9c)+(-2b+3c-a)] - (2a-3b+4c)
= [a+3b-4c+4a-b+9c-2b+3c-a] - (2a-3b+4c)
= [a+4a-a+3b-b-2b-4c+9c+3c] - (2a-3b+4c)
= [4a+8c] - (2a-3b+4c)
= 4a+8c-2a+3b-4c
= 2a+3b+4c


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