Question

AR
C
72°
b
D
B i) state the value of a
ii) name the vertically opposite angle
iii) name the adjacent angle
iv) does the figure prove that the vertically opposite angle are equal
v) name the obtuse angles​

Answer 1

Therefore,

∠AOC+∠COD+∠BOD=180°⇒(3x−6)°+55°+(x+20)°=180⇒4x=111°⇒x=27.5°∠AOC+∠COD+∠BOD=180°⇒3x-6°+55°+x+20°=180⇒4x=111°⇒x=27.5°

Hence,

∠AOC=3x−6∠AOC=3x-6

=3×27.5−6=76.5°=3×27.5-6=76.5°

and ∠BOD=x+20∠BOD=x+20

=27.5+20=47.5°=27.5+20=47