Ar of circle of r=5 is nimericaaly what percent of its circimfre
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Area of the circle
= πr^2
= (3.14 × 5 × 5) m^2
Circumference of the circle
= 2πr
= (2 × 3.14 × 5) m
Percentage of Circumference with respect to Area
= [(2 × 3.14 × 5)/(3.14 × 5 × 5)] × 100
= (2/5) × 100
= 2 × 20
= 40 %
= πr^2
= (3.14 × 5 × 5) m^2
Circumference of the circle
= 2πr
= (2 × 3.14 × 5) m
Percentage of Circumference with respect to Area
= [(2 × 3.14 × 5)/(3.14 × 5 × 5)] × 100
= (2/5) × 100
= 2 × 20
= 40 %
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