Question

(ar (PBQ) (ARC)
8. In Fig. 9.34, ABC is a right triangle right angled at A. BCED, ACFG and ABMN a
squares on the sides BC, CA and AB respectively. Line segment AX IDE meets BC
at Y. Show that
D X
Fig. 9.34
() A MBC & A ABD
(ii) ar (BYXD)=2 ar (MBC)
(iii) ar (BYXD) ar (ABMN)
(iv) AFCB = A ACE
(v) ar (CYXE) 2 ar (FCB)
(vi) ar (CYXE) = ar (ACFG)
(vii) ar (BCED) ar (ABMN)+ ar (ACFG)
Note: Result (vii) is the famous Theorem of Pythagoras. You shall learn a simpler
proof of this theorem in Class X.​

Answer 1

Answer: please insert the picture of the particular diagram for clarification of the question.i think that would be better for both the users that so and those that answers

Step-by-step explanation: