अर्थपूर्ण वाक्य गैंहु हवा करोना अस्पताल रोटी गाय बरसात टेलीविजन खेल अभ्यास
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I don't understand your question
See the attachment for a labelled diagram of the circuit .
Here , we can clearly see that CE , EF , and FD are in series .
Equivalent resistance between them : 10 Ω + 20Ω + 20Ω = 50 Ω .
Now CD and the previous equivalent resistance are in parallel .
New Equivalent Resistance = 50×30/(50+30) = 1500/80 = 150/8 = 185 Ω .
This 185 Ω is parallel with the other two 10 Ω resistors .
Thus the final equivalent resistance becomes 205 Ω.
Answer - The equivalent resistance is 205 Ω .
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