Aray of light makes an angle of 10° with the horizontal above it and strikes a plane mirror which is inclined at an angle O to the horizontal. The angle O for which the reflected ray becomes vertical is 10 degree
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Angle between the reflected and incident ray = 80 (Final ray is vertical and incidence is 10 wrt horizontal)
Angle of incidence = angle of reflected ray = 40
Angle of reflected ray with mirror = 90 – 40 = 50
So, angle with horizontal = 90 – 50 = 40
Angle of incidence = angle of reflected ray = 40
Angle of reflected ray with mirror = 90 – 40 = 50
So, angle with horizontal = 90 – 50 = 40
Answered by
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Answer
the reflected and incident ray = 80 (Final ray is vertical and incidence is 10 wrt horizontal)
Angle of incidence = angle of reflected ray = 40
Angle of reflected ray with mirror = 90 – 40 = 50
So, angle with horizontal = 90 – 50 = 40
Thank you
the reflected and incident ray = 80 (Final ray is vertical and incidence is 10 wrt horizontal)
Angle of incidence = angle of reflected ray = 40
Angle of reflected ray with mirror = 90 – 40 = 50
So, angle with horizontal = 90 – 50 = 40
Thank you
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