Question

ARB represent a semicircular plate where AB=14cm .A semicircle ASO is cut away (O is the mid point of AB )what is the area of the remaining portion ? (take π=22/7)

Answer 1

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Answer 2

area of semi circle ARB=πr²/2
radius of semi circle=14/2=7cm

area=22×49/14=77cm²

area of ASO=πr²/2
radius of ASO=7/2=3.5cm

area=22×12.25/14=19.25cm²



area of remaining portion =( 77-19.25)cm²
=57.75cm²