ARB represents a semi-circular plate AB=14cm. A semi-circle ASO is cut away (O is the midpoint
of AB). What is the area of the remaining portion?
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Answer:
Step-by-step explanation:
AO=OB=
2
AB
=7cm
ASO is cut away from ARO plate
⇒ Remaining Area = shaded region
⇒ Area = Area of large semicircle - Area of small semi circle
radius of large circle = AO=7cm=R(let)
radius of small circle = AO
′
=
2
7
cm=r(let)
⇒ required Area =
2
πR
2
=
2
πr
2
=
2
π
[(7)
2
−(
2
7
)
2
]
=
7×2
22
[49−
4
49
]
=
14
22
×
4
3×49
=
4
33×7
=57.75cm
2
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