Question

ARB represents a semicircular plate where AB = 14 cm . A semicircular ASO is cut away .(o is the midpoint of AB ). What is the area of remaining portion

Answer 1

ARB is a semicircle with diameter AB and radius AO
AB=14cm
AO=7cm=R
now ASO is cut away FROM ARB with diameter AO
radius =7/2cm=r
area of remaining portion =area ARB -area ASO
=PIE R^2-pie r^2
=22/7.49-22/7.49/4
=22/7.147/4
=231/2=115.5cm^2