Question

arc ab : arc bc = 2:1 angle AOB=108⁰ where O is the centre of the circle find BOC OAC BAC​

Answer 1

$\huge\mathfrak\pink{Answer}$

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We know that when two arcs are in ration 2:1 then the subtended

by them is also in the ratio 2:1

As given arc AB is twice the length of arc BC

Therefore, arc AB:arc BC=2:1

Hence, ∠AOB:∠BOC=2:1

Now give that ∠AOB=100o

so, ∠BOC=21∠AOB=21×100o=50o

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$\huge\mathfrak\red{Thanks}$

I hope it will help you.