Question

arc ab is congruent to ac o is the centre bc is chord prove oa is perpendicular bisector of bc

Answer 1

let ao meet BC at m. Equal arcs subtend equal angles at the centre. ∆OCB is isoceles. oc=ob [radii]
now the ∆OMC is congruent with ∆OMB. [ASA]
therefore, angle omc and angle OMB are equal . so, each of them will be 90°. [ CMB is a straight line]

Answer 2

Answer:

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