arc ABC is inscribed with angle ABC with O be the centre of circle then if m angleACB=34° then m(arcACB)=
Answers
Answer:
m(arcACB)=68°
Step-by-step explanation:
angle ACB= 1/2 m(arc ACB)
angle ACB×2= m(arc ACB)
34×2= m(arc ACB)
m(arc ACB)=68°
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Given : Arc ABC is inscribed with angle ACB with O be the centre of circle then angle ACB = 34°
To Find : m arc (ACB )
Solution:
∠AOB = 2 ∠ACB
∠ACB = 34°
=> ∠AOB = 2 ( 34°)
=> ∠AOB = 68°
m arc (ACB ) = 360° - ∠AOB
=> m arc (ACB ) = 360° -68°
=> m arc (ACB ) = 292°
m arc (ACB ) = 292°
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