arc ABC is inscribed with <ACB with O be the centre of the circle then then if m<ABC=34 then m (arc ACB) =?(1)17(2)34(3)192(4)144
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Given : Arc ABC is inscribed with angle ACB with O be the centre of circle then angle ACB = 34°
To Find : m arc (ACB )
(1)17(2)34(3)292(4)144
Solution:
∠AOB = 2 ∠ACB
∠ACB = 34°
=> ∠AOB = 2 ( 34°)
=> ∠AOB = 68°
m arc (ACB ) = 360° - ∠AOB
=> m arc (ACB ) = 360° -68°
=> m arc (ACB ) = 292°
m arc (ACB ) = 292°
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