Question

Arc AC and arc BD are equal i.e. BC is the common arc and
∟AOB=30°, Find ∟COD where O is the center of circle.

Answer 1

Given :  Arc AC and arc BD are equal  

BC is the common arc

∠AOB = 30°

To Find : ∠COD

where O is the center of circle.

Solution:

Arc AC and arc BD are equal

=> ∠AOC = ∠BOD

∠AOC = ∠AOB + ∠BOC

∠BOD = ∠BOC + ∠COD

=> ∠AOB + ∠BOC = ∠BOC + ∠COD

=> ∠AOB   =   ∠COD

∠AOB = 30°

=> ∠COD  = 30°

Learn more:

In the given figure angle 25 degrees find bdc dba and cob - Brainly.in

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Angle cab=25° find angle bdc,angle dba and anglecob - Brainly.in

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Answer 2

$\mathfrak\green{☞Solution}$

$\mathtt\blue{Arc \: AC \: and \: BD \: are \: equal}$

$\mathtt\blue{\angle{AOC} = \angle{BOD}}$

$\mathtt\blue{\angle{AOC} = \angle{AOB} + \angle{BOC}}$

$\mathtt\blue{\angle{BOD} = \angle{BOC} + \angle{COD}}$

$\mathtt\blue{ = \angle{AOB} + \angle{BOC} = \angle{BOC} + \angle{COD}}$

$\mathtt\blue{ = > \angle{AOB} + \angle{COD}}$

$\mathtt\red{\angle{AOB}} = \mathtt\red{30°}$

$\mathtt\red{\angle{COD}} = \mathtt\red{30°}$