Arc of sector is one sixth area of corresponding circle find the area of sector
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area of sector of a circle is 1/6 of area of circle
\frac{\theta}{360}\times \pi r^{2}=\frac{1}{6}\times \pi r^{2}
\implies \theta= \frac{360\times \pi r^{2}}{6\times \pi r^{2}}
After cancellation, we get
theta = 60 \degree
Therefore,
degree\:measure \: of \\minor \: arc = 60 \degree
Hope it helps u my friend
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