Arc properties of a circle (Grade 9)
solve the following:-
find x
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From O, draw OM perpendicular to AB.
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ BM = (
16
2
) cm=8 cm
In the right ΔOMB, we have:
OB2 = OM2 + MB2 (Pythagoras theorem)
⇒ 102 = OM2 + 82
⇒ 100 = OM2 + 64
⇒ OM2 = (100 - 64) = 36
⇒ OM=
√
36
cm=6 cm
Hence, the distance of the chord from the centre is 6 cm.
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