are
101. Take five simple equantions and
Check whether they
satisfied with value 1,2,3or4
Answers
Answer:
(i) x + 3 = 0
L.H.S. = x + 3
By putting x = 3,
L.H.S. = 3 + 3 = 6 ≠ R.H.S.
∴ No, the equation is not satisfied.
(ii) x + 3 = 0
L.H.S. = x + 3
By putting x = 0,
L.H.S. = 0 + 3 = 3 ≠ R.H.S.
∴ No, the equation is not satisfied.
(iii) x + 3 = 0
L.H.S. = x + 3
By putting x = −3,
L.H.S. = − 3 + 3 = 0 = R.H.S.
∴ Yes, the equation is satisfied.
(iv) x − 7 = 1
L.H.S. = x − 7
By putting x = 7,
L.H.S. = 7 − 7 = 0 ≠ R.H.S.
∴ No, the equation is not satisfied.
(v) x − 7 = 1
L.H.S. = x − 7
By putting x = 8,
L.H.S. = 8 − 7 = 1 = R.H.S.
∴ Yes, the equation is satisfied.
(vi) 5x = 25
L.H.S. = 5x
By putting x = 0,
L.H.S. = 5 × 0 = 0 ≠ R.H.S.
∴ No, the equation is not satisfied.
(vii) 5x = 25
L.H.S. = 5x
By putting x = 5,
L.H.S. = 5 × 5 = 25 = R.H.S.
∴ Yes, the equation is satisfied.
(viii) 5x = 25
L.H.S. = 5x
By putting x = −5,
L.H.S. = 5 × (−5) = −25 ≠ R.H.S.
∴ No, the equation is not satisfied.
(ix) = 2
L.H.S. =
By putting m = −6,
L. H. S. = ≠ R.H.S.
∴No, the equation is not satisfied.
(x) = 2
L.H.S. =
By putting m = 0,
L.H.S. = ≠ R.H.S.
∴No, the equation is not satisfied.
(xi) = 2
L.H.S. =
By putting m = 6,
L.H.S. = = R.H.S.
∴ Yes, the equation is satisfied.
Given : value 1,2,3 or 4.
To Find : make any five simple equations
Solution:
Equations :
x + 2 = 3
x + 5 = 7
x + 3 = 6
x + 1 = 5
x + 2 = 3
x = 1
=> 1 + 2 = 3 satisfied
x = 2
=> 2 + 2 = 4 ≠ 3 not satisfied
x = 3
=> 3+ 2 = 5 ≠ 3 not satisfied
x = 4
=> 4 + 2 = 6 ≠ 3 not satisfied
Hence 1 satisfy , 2 , 3 and 4 Does not satisfy
Similarly for
x + 5 = 7
2 satisfy , 1 , 3 , 4 Does not satisfy
x + 3 = 6
3 satisfy , 1 , 2 , 4 Does not satisfy
x + 1 = 5
4 satisfy , 1 , 2 , 3 Does not satisfy
Learn More:
Solve the following x+y/xy=5 and x-5/xy=7 - Brainly.in
brainly.in/question/8168066
solve for x and y : x+y/xy=2,xy/=6
brainly.in/question/12892518