Question

are
(2) The perimeter of two squares
56 m and 192 m respectively. Find the
perimeter of another square, equal in
area to the sum of the area of the
first two squares.​

Answer 1

Length of a side of square having perimeter 192 = 192/4 = 48 cm

Similarly, length of side of square with perimeter 56 = 56/4 = 14 cm

Since area of a square = (side)^2,

Total area of both squares = 48^2 + 14^2

= 2500cm^2

Let side of square whose perimeter is to be found be x cm

Then, according to given question

x^2 = 2500

X = 50 cm

Therefore, perimeter is equal to 50*4 = 200cm