Are f(x) = x3 - 1 and g(x) = (x + 1)1/3 inverse functions?
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Answer:
yes they are.
Step-by-step explanation:
let f(x)=y then , x = f inverse of y
3x-1=y
x=(y+1)/3
f inverse of y = (y+1)/3
f inverse of x =(x+1)/3
and that is equal to g(x).
hence proved
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