Question

are
FB 6:3 g of Sodium bicarbonate
ladded to
15g of Ethanaic
the residu
left is found to be 18 what
mass of con is released
is released in this
reaction?​

Answer 1

Answer:

Solution :

The chemical equation for the reaction is :

NaHCO3+CH2COOH→CH3COONa+H2O+CO2

Sod. Bicarbonate Acetic acid Sod. acetate⏟(Residue)

Mass of reactants = Mass of NaHCO3+Mass ofCH3COOH=6.3+15=21.3g

Mass of product = Mass of residue + Mass of CO2=18+3.3=21.3g

Since these is no change in mass during the chemical reaction the data illustrates the Law of conservation of Mass.

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