Are magnetic lorentz force and electric lorentz force opposite to each other?
Answers
Answer:
In addition, the magnetic force acts in a direction that is perpendicular to the direction of the field. In comparison, both the electric force and the electric field point directly toward or away from the charge.
Answer:
There is nothing under the blue sky by the title of "Lorentz Force" as defined to be working according to the mathematics offered theoretically.
For example , you read on Wikipedia :
" In many textbook treatments of classical electromagnetism, the Lorentz force law is used as the definition of the electric and magnetic fields E and B.[6][7][8] To be specific, the Lorentz force is understood to be the following empirical statement:
The electromagnetic force F on a test charge at a given point and time is a certain function of its charge q and velocity v, which can be parameterized by exactly two vectors E and B, in the functional form:{\displaystyle \mathbf {F} =q(\mathbf {E} +\mathbf {v} \times \mathbf {B} )}
This is valid, even for particles approaching the speed of light (that is, magnitude of v, |v| ≈ c).[9] So the two vector fields E and B are thereby defined throughout space and time, and these are called the "electric field" and "magnetic field". The fields are defined everywhere in space and time with respect to what force a test charge would receive regardless of whether a charge is present to experience the force.
" AS A DEFINITION OF E AND B, THE LORENTZ FORCE IS ONLY A DEFINITION IN PRINCIPLE BECAUSE A REAL PARTICLE (AS OPPOSED TO THE HYPOTHETICAL "TEST CHARGE" OF INFINITESIMALLY-SMALL MASS AND CHARGE) WOULD GENERATE ITS OWN FINITE E AND B FIELDS, WHICH WOULD ALTER THE ELECTROMAGNETIC FORCE THAT IT EXPERIENCES.[CITATION NEEDED] IN ADDITION, IF THE CHARGE EXPERIENCES ACCELERATION AS IF FORCED INTO A CURVED TRAJECTORY, IT EMITS RADIATION THAT CAUSES IT TO LOSE KINETIC ENERGY. SEE FOR EXAMPLE BREMSSTRAHLUNG AND SYNCHROTRON LIGHT. THESE EFFECTS OCCUR THROUGH BOTH A DIRECT EFFECT (CALLED THE RADIATION REACTION FORCE) AND INDIRECTLY (BY AFFECTING THE MOTION OF NEARBY CHARGES AND CURRENTS). "
Even if you wanna think relatively , again the trajectory as per predictions based on the LF mathematics has to be modulated to be able to contain real particle behavior in the ambience where the LF is supposed to be extant. Of particular interest here is the fact that the Motion Of Charged Particles In Magnetic Fields within the Riemannian or pseudo-Riemannian metric would be locally homogeneous if any two points can be connected by flowing along a finite sequence of local Killing fields. The study of such metrics is a traditional field in differential geometry. Now , you may read from { https://hal.archives-ouvertes.fr/hal-00935722v2/document } THAT :
" If, for a contradiction , there exists a g-invariant vector field X in U of constant strictly negative g-norm, then the g-action on R(U) preserves a subbundle R ′ (U) with structural group H ′ , where H ′ is the stabilizer of a strictly negative vector in the standard linear representation of PSL(2,R) on R to the power 3(R3) . In this case, H ′ is a compact one parameter group in PSL(2,R). The previous argument works, replacing the Kostant-Rosenlicht theorem by the obvious fact that orbits of smooth compact group actions are closed. "
This dualism boils down to the equality of the spatial part of the four-vector and the three-vector practically only for position and momentum. However, already for velocity or force, spatial parts of the dual quantities differ by the Lorentz factor. The manifolds procreated by electric and magnetic fields do not persist to the moment when a charged particle is assumed to be in interaction with them only on a point-set basis ground. This does NOT mean that there is no interaction: the interaction is not yet fully geometrically elucidated.
Explanation: