Question

Are moderators here for only deleting questions and answers? they are so active in deleting but no one wud answer my questions why? therefore I am offering 50 POINTS NOW ANSWER PLS.. 60ml of N2+ 60ml of H2 give product's composition and volume.​

Answer 1

Answer:

Let the given mixture contains 2x ml of NO. The volume of N2O present is 60−2x ml.

The balanced chemical equations are as shown below.

2x2NO+2H2→xN2+2H2O

60−2xN2O+H2→60−2xN2+H2O

The volume of nitrogen collected is 38  ml.

Hence, 60−2x+x=38

x=22ml

Hence, the volumes of NO and N2O present in the originl mixture are 2x=2(22)=44ml  and  60−2(22)=16ml respectively.

Answer 2

Answer:

Hope it will give you some hint to complete your answer.

Explanation:

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