Question

Are of triangle side 8cm,15cm,19cm

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Question :---- Find the Area of ∆ with sides 8cm, 15cm and 19cm.

Formula used :---

Triangle :--- is a plane figure with three straight sides and three angles.

→ Area of ∆ = √( s(s-a)(s-b)(s-c) ) [ where s = (a+b+c)/2 ]

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Solution :----

Given ,

→ a = 8cm

→ b = 15cm.

→ c = 19cm.

So,

→ Semi-Perimeter = (a+b+c/2)

→ s = (8+15+19)/2

→ s = 42/2

→ s = 21 cm.

Putting all values in above told formula now, we get,

→ Area of ∆ = √21*(21-8)*(21-15)*(21-19)

→ Area of ∆ = √21*13*6*2

→ Area of ∆ = √3*7*13*12

→ Area of ∆ = √36*91

→ Area of ∆ = 6√91 cm²

Hence, Area of ∆ will be 6√91 cm².