Question

are rational numbers existence of identity in multiplicative properties​

Answer 1

Answer:

hey mate, good afternoon

Two rational numbers can be multiplied in any order.

Step-by-step explanation:

(i) Let us consider the rational numbers 3/4 and 5/7 Then,  

(3/4 × 5/7) = (3 × 5)/(4 × 7) = 15/28 and (5/7 × 3/4) = (5 × 3)/(7 × 4)

= 15/28

Therefore, (3/4 × 5/7) = (5/7 × 3/4)  

(ii) Let us consider the rational numbers -2/5 and 6/7.Then,  

{(-2)/5 × 6/7} = {(-2) × 6}/(5 × 7) = -12/35 and (6/7 × -2/5 )  

= {6 × (-2)}/(7 × 5) = -12/35

Therefore, (-2/5 × 6/7 ) = (6/7 × (-2)/5)

(iii) Let us consider the rational numbers -2/3 and -5/7 Then,  

(-2)/3 × (-5)/7 = {(-2) × (-5) }/(3 × 7) = 10/21 and (-5/7) × (-2/3)  

= {(-5) × (-2)}/(7 × 3) = 10/21  

Therefore, (-2/3) × (-5/7) = (-5/7) × (-2)

thank you hope it was help full