Question

are rectangular field has 80 metre length and 48 metre breadth three rows each off with two metre pass through the fill such that two roads are parallel to the breadth and third row parallel to the length find the area covered by three roads​

Answer 1

Answer:

Step-by-step explanation:

We know that width of each road is 2m.

Length of two of the roads (parallel to the breadth) = breadth = 48m.

Length of one road (parallel to the length) = length = 80m.

i] Area of two roads parallel to the breadth = 2(width * breadth)

                                                             = 2( 2*48)

                                                             = 2(96)

                                                             = 192 m. square

ii] Area of road parallel to the length = width of road * length 

                                                    = 2 * 80 

                                                    =  160 m. square

Now, subtract the areas common in both the roads :

 We can see that the length and breadth of these common areas is 2 m.

Areas of the common part = (2*2) + (2*2)

                                      = 4 + 4 

                                      = 8 m. square

Upon subtracting these from the total area of the roads :

    (192 + 160) - 8

    344 m. square

 The area covered by the three roads is 344 m. square.

Look at the attachment.

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