are roots of (b-c) x^2+2(c-a) x+a-b=0 real?
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Step-by-step explanation:
(b-c) x^2+2(c-a) x+a-b = 0
L. H. S - [(b-c) x . 2 ]+ [2 . (c-a) x]+a-b
=[ 2bx-2cx + 2cx-2ax ]+ a-b
= 2bx-2ax+a-b
= 2x(b-a) +a-b
= 2x. b-a+a-b
= 2x. 0
= 0 R. H. S [ proved ]
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