α,β are roots of y²-2y-7=0 find, a²+β²
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Hi ,
Here I am using p , q instead of alfa and beta.
Compare y² - 2y - 7 = 0 with ay²+by+c = 0 ,we
get
a = 1 , b = -2 , c = -7
i ) sum of the roots = -b/a
p + q = - ( -2 )/1 = 2 ----( 1 )
ii ) product of the roots = c/a
pq = -7/1 = -7 ---( 2 )
Now ,
p² + q² = ( p + q )² - 2pq
= 2² - 2 × ( -7 )
[ from ( 1 ) and ( 2 ) ]
= 4 + 14
= 18
Therefore ,
alfa² + beta² = 18
I hope this helps you.
: )
Here I am using p , q instead of alfa and beta.
Compare y² - 2y - 7 = 0 with ay²+by+c = 0 ,we
get
a = 1 , b = -2 , c = -7
i ) sum of the roots = -b/a
p + q = - ( -2 )/1 = 2 ----( 1 )
ii ) product of the roots = c/a
pq = -7/1 = -7 ---( 2 )
Now ,
p² + q² = ( p + q )² - 2pq
= 2² - 2 × ( -7 )
[ from ( 1 ) and ( 2 ) ]
= 4 + 14
= 18
Therefore ,
alfa² + beta² = 18
I hope this helps you.
: )
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