Question

Are the following pair of linear equations consistent? Justify your answer (1) -3x-4y=12 4y+3x=12​

Answer 1

Answer:

yes, they have unique solution

Step-by-step explanation:

because a1/a2 =/= b1/b2

hope this helps u...

Answer 2

Answer:

condition for pair of linear equations

a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0

(i) consistent with unique solution is

a1/a2 ≠ b1/b2

(ii) consistent with infinitely many

solution is a1/a2 = b1/b2 = c1/c2

-3x-4y=12 .....(1)

-3x-4y-12=0

a1 = -3 b1 = -4 c1 = -12

4y+3x=12 .......(2)

3x+4y-12=0

a2 = 3 b2 = 4 c2 = -12

a1/a2 = -3/3 = -1

b1/b2 = -4/4 = -1

c1/c2 = -12/-12 = 1

a1/a2 = b1/b2 = -1

hence do not satisfy the first condition

a1/a2 = b1/b2 ≠ c1/c2

-1 = -1 ≠ 1

hence do not satisfy the second condition

so, the given pair of linear equations are not consistent