Question

Are the following sets are equal A={x:x^3-8=0&x is real number}B ={x:x^2+7x-18=0&x>/0}

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Answer 1

QUESTION -

Are the following sets are equal A={x:x^3-8=0&x is real number}B ={x:x^2+7x-18=0&x>/0}

ANSWER -

For set A:-

x^3 - 8 = 0

so

x^3 = 8

therefore the solution is

x = 2

( it is real number)

For set B:-

x^2 - 7x - 18 = 0

First, factor the polynomial

(x + 2)(x - 9) = 0

Set both factors equal to 0

x + 2 = 0

x - 9 = 0

Solve for x

x = -2

x = 9

Hence, Both set have unequal elements.

So A ≠ B

Answer 2

$\Huge{\red{\underline{\textsf{ANSWER}}}}$

★ For set A:-

x^3 - 8 = 0

so

x^3 = 8

therefore the solution is

x = 2

( it is real number)

★ For set B:-

x^2 - 7x - 18 = 0

First, factor the polynomial

(x + 2)(x - 9) = 0

Set both factors equal to 0

x + 2 = 0

x - 9 = 0

Solve for x

x = -2

x = 9

• Hence, Both set have unequal elements.

★ So A ≠ B