Question

are
The mean and variance of a binomial distribution
4 and 4/3 respectively. Find the
P(X >=1) P(X<=4)P(1< X<5) P(x>3) P(X<6)​

Answer 1

Step-by-step explanation:

mean=np=4. ...........1

variance=npq=4/3 ...... 2

substitute in eq 1 in eq 2 we get

q = 1/3

p=2/3

n= 6

now the rest can be done using formula ncr p raise to r * q raise to n-r