Are the point A ( 4,5 ) B (7,6) C ( 6,3) are collinear
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Answered by
26
Slope of AB = (6-5)/(7-4) = 1/3
Slope of BC = (3-6)/(6-7) = 3
Slope of AC = (3-5)/(6-4) = -1
It is clear that the slopes are unequal.
So the points are not collinear, they form a triangle.
Hope it may help you !!!!!
Slope of BC = (3-6)/(6-7) = 3
Slope of AC = (3-5)/(6-4) = -1
It is clear that the slopes are unequal.
So the points are not collinear, they form a triangle.
Hope it may help you !!!!!
Answered by
18
Answer:
If points are collinear, therefore
Area of triangle = 0
1/2{x1(y2-y3) + x2(y3-y1) + x3(y1- y2)=0
1/2{ 4(6-3) +7(3-5) +6(5-6) }=0
1/2{4(3) +7(-2) +6(-1) }=0
1/2{12-14-6}=0
1/2{ -8}=0
-4 =0
This implyies the points are not collinear.
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