Are the points (-2,2),(8,-2) and (-4,3) are the vertices of a right angle triangle
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Answer:
No
Step-by-step explanation:
Let the points A(-2, 2), B(8, -2) and C(-4, 3) be the vertices of a triangle ABC.
Using Pythagoras theorem
⇒ AB 2 + AC 2 = BC 2
AB 2 = (8 + 2) 2 + (-2 - 2) 2 = 10 2 + 4 2 = 100 + 16 = 116
BC 2 = (-4 - 8) 2 + (3 + 2) 2 = (-12) 2 + 5 2 = 144 + 25 = 169
AC 2 = (-4 + 2) 2 + (3 - 2) 2 = (-2) 2 + 1 = 4 + 1 = 5
⇒ AB 2 + AC 2 ≠ BC 2
The above vertices are not points of a right angled triangle.
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