Question

are the points(3,2),(-2,-3) and(2,3) from a triangle​

Answer 1

Answer:

Points are(3,2),(-2,-3),(2,3).

therefore by area of triangle.

0=1/2*(x1(y1-y2)+x2(y3-y2)+x3(y1-y3)

0*1/2=3(2-(-3)+(-2)(3-(-3)+2(2-3)

0=3(-5)+(-2)(-6)+2(-1)

=(-15)+12+(-2)

=(-3)-2

=5.