Math, asked by lathagadde555, 1 day ago

are The sides of a triangle given by 3x-y; 4x^2 -7xy +4y; - 3x + 7xy + 8y^2 find its Perimeter and

Answers

Answered by joannatheresa6c

1

Answer:

perimeter of triangle ABC = AB + BC +AC

= 3x^2-y^2+4x^2-7xy+4y^2-3x^2+7xy+8y^2

= 4x^2+11y^2

Step-by-step explanation:

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