Question

, are the zeros of the quadratic polynomial f (x) = x² + px + 45.

Find the value of P if – =12.​

Answer 1

Answer:

f(x)=x²+p(x)+45.

x=12.

f(12)=(12)²+p(12)+45.

f(12)=144+12p+45.

12p=-144-45.

12p=-189. (Because -×-=+ & largest number is important).

p=-189/12.

I think this is your answer.