Question

ARE U GUYS READY FOR TOMORROWS BOARDS MATHS PAPER

IF U ARE THEN SOLVE THIS QUESTION !!!!!!

IF cosФ + sinФ = √2 cosФ

PROVE : cosФ - sinФ = √2 sinФ

WHO EVER ANSWERS GETS 99 POINTS !!!!!

Answer 1

Heya☺


Squaring both the sides

(cosa + sina )^2 = (√2cos)^2
cos^2a + sin^2a + 2cosa sina = 2cos^2a

sin^2a + 2cosa sina = cos^2a
2cosa sina = cos^2a - sin^2a

2cosa sina = (cosa + sina)( cosa - sina)

2cosa = √2cosa ( cosa - sina)
2cosa/√2cosa = cosa - sina

✔ √2 cosa = cosa - sina

✴Hope it helps u❕

✌✌All the best for ur exam

Answer 2

Hey mate ^_^

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Answer:
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CosФ + SinФ = √2 CosФ

SinФ = √2 CosФ - CosФ

SinФ = CosФ (√2-1)

Now,

Multiplying by (√2+1) on both the sides.

Sin (√2+1) = CosФ(√2-1)(√2+1)

√2 SinФ + SinФ = CosФ(2-1)

CosФ - SinФ= √2 SinФ

#Be Brainly❤️