Question

area 144 sqcm, base 16 cm , find height of parallelogram.


Answer sincerely otherwise i will report to u​

Answer 1

Given : Area of the Parallelogram is 144 cm² and its base is 16 cm .

To Find : Find the Height of Parallelogram

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SolutioN :

$\dag$ Formula Used :

• ${\underline{\boxed{\pmb{\sf{ Area{\small_{(Parallelogram)}} = Base \times Height }}}}}$

$\dag$ Calculating the Height :

$\begin{gathered} \qquad \; \; \dashrightarrow \; \; \sf { Area = Base \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \; \dashrightarrow \; \; \sf { 144 = 16 \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \; \dashrightarrow \; \; \sf { \dfrac{144 }{16} = Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \; \dashrightarrow \; \; \sf { \cancel\dfrac{144 }{16} = Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \; \dashrightarrow \; \; {\underline{\boxed{\pmb{\sf{ Height = 9 \; cm }}}}} \; {\red{\pmb{\bigstar}}} \\ \\ \\ \end{gathered}$

$\therefore \;$ Height of the Parallelogram is 9 cm .

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Answer 2

$\underline{\textbf{\textsf{Question :-}}}$

• Find the Height of Parallelogram, if the Area of Parallelogram is 144 cm² and the Base is 16 cm .

$\underline{\textbf{\textsf{Answer :-}}}$

• Height of Parallelogram is 9 cm .

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Given :-

• Area of Parallelogram = 144 cm²
• Base of Parallelogram = 16 cm

To Find :-

• Height of Parallelogram = ?

Solution :-

• As per the given condition, we have provided Area of Parallelogram 144 cm² . Base is given 16 cm . And, we have to calculate the Height .

➻ Formula Required :-

• $\sf{Area \: of \: Parallelogram \: = \: Base \times Height}$

➻ By substituting the values :-

$\dag \: \: \sf{Area \: of \: Parallelogram \: = \: Base \times Height}$

$\Longrightarrow \: \: \sf{144 \: = \: 16 \: \times \: Height}$

$\Longrightarrow \: \: \sf{Height \: \: = \: \: \frac{144}{16} }$

$\Longrightarrow \: \: \bf{Height \: = \: 9 \: cm}$

Hence :-

• Height of Parallelogram = 9 cm

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$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Square = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \sf{Area \: of \: Rectangle = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Triangle = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Parallelogram = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Trapezium = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf {Area \: of \: Rhombus = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}$